Grouping array items with groupBy()

This API has changed twice in the name of web compatibility, so be aware that some older blog posts are now completely out of date. Chrome Canary has shipped an implementation that is up-to-date with the spec. Safari had shipped the older version. This has been updated in Safari Technology Preview. Firefox supported the old method behind a flag and has not yet shipped an update.


The first argument to groupBy is an array or any other iterable. The second is a callback function.

This example seperates numbers into two groups depending on whether they are odd or even:

const randomNumbers = [24, 32, 49, 10, 9, 7, 1082, 88, 101];
const groupedNumbers = Object.groupBy(randomNumbers, num => num % 2 === 0 ? 'even' : 'odd');

The return value is an object. groupedNumbers.even now contains all the even numbers and groupedNumbers.odd contains all the odd numbers.

The next example groups names by their first letter:

const namesArray = ['Barry', 'Mary', 'Bruce', 'William', 'Wendy', 'Mark'];
const names = Object.groupBy(namesArray, name => name[0].toLowerCase());

names.b would then be ['Barry', 'Bruce']

Here’s an example that takes an array of film objects and groups the objects by genre:

const films = [{
    name: 'Team America',
    genre: 'comedy'
}, {
    name: 'Rambo',
    genre: 'action'
}, {
    name: 'Airplane!',
    genre: 'comedy'
}, {
    name: 'Die Hard',
    genre: 'action'
}, {
    name: 'Borat',
    genre: 'comedy'

const filmsByGenre = Object.groupBy(films, film => film.genre);

There is also an equivalent Map.groupBy(). Rather than returning an object, it returns a Map.